Jump to content
  TPR Home | Parks | Twitter | Facebook | YouTube | Instagram 

ih8rollercoasters

Members
  • Posts

    3
  • Joined

  • Last visited

ih8rollercoasters's Achievements

Newbie

Newbie (1/14)

  • First Post
  • Week One Done
  • One Month Later
  • One Year In

Recent Badges

0

Reputation

  1. Technically you're correct, but heavily splitting hairs. In Engineering CAD refers to Computer Aided Drafting, software that draws up objects in 2-and 3D. Other packages that do other design aspects (CFD, FEA, Numerical Methods, Gas Dynamics) are not referred to as CAD, rather by what portion of design work they actually do. PATTYCAKES has a more correct argument in this context, in my time working in Engineering CAD has always specifically referred to drafting software. Back on topic, when does Toronto's schools go back in session? May be passing through the area in mid-August/early-September and would rather not fight every kid and their mom if I end up there.
  2. Probably just a pick point for a block-and-tackle, keep the hoist motor low for ease of access.
  3. Long time lurker, first time poster, one comment here needs some clarification. Centrifugal force isn't a myth, it's a perfectly valid force. I imagine your interpretation of the word "fictitious" is tripping you up, you have to think outside Newton's Laws to understand it. Newton's Second Law says F = ma, if you don't have acceleration you don't have force. But have you ridden in a car around a corner and been thrown to the outside of the car while traveling at a constant speed? That makes no sense, F = ma says there's no acceleration so there's no force! And that's absolutely true, if you're using the standard inertial reference system used by Newton and traveling in a straight line. But if you use a rotating reference plane to account for the corner, rotating at an angular speed "ω" in degrees/second, you find there's an angular acceleration being produced by traveling around the corner. "Aha!" you may say, there's an acceleration which causes a force to be produced, and this is the centrifugal force that is supposedly "fictitious". If you really want to know the math the equation for centrifugal force is F = m*(ω^2)*r, hope that helps you understand why parks still refer to a perfectly valid force calculation when marketing rides. I can't think of any myths/rumors that haven't already been said, some good ones have been posted here for sure.
×
×
  • Create New...

Important Information

Terms of Use https://themeparkreview.com/forum/topic/116-terms-of-service-please-read/