This question was previously asked in

RRB ALP Previous Paper 19 (Held On: 30 Aug 2018 Shift 1)

Option 3 : 240 J

Cell

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10 Questions
10 Marks
7 Mins

The correct answer is __240 J__.

__Key Points__

- When a
**force is applied**to an object which causes**displacement along the direction of force then the work is said to be done by that force.** - The work done by a force is defined as
**"the product of the component of the applied force on the block in the direction of the displacement and the magnitude of this displacement"**is called**work done**.

__Additional Information__

- i.e., \(W = \vec F.d\vec x = Fdx\cos \theta \)

or in terms of magnitude, it can be given as

\(W\; = \;F \times s\)

- Here both
**force and displacement**will be along the same direction since force is**causing this displacement**thus Work done is a scalar quantity.- Here,
**Force applied on object**= F**Displacement of object**= dx**Distance traveled by an object**= s**The angle between Force and displacement**= θ

**Calculation:**- Given that,
- Person raised the box of
**weight 120 N**through the**height of 2 m** - i.e.,
**F = 120 N** **x**= 2 m

- Thus from the above explanation, we can see that
**Work = Force × Distance**moved in the**direction of the force**- Force of
**120 N**is acting downwards, Therefore**Work Done**= 120 × 2 =**240 J**