A body moves, from rest with a constant acceleration of 5 m/s^{2}. The distance covered in 5 sec. is:

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NPCIL Stipendiary Trainee ME 2018

Option 2 : 62.5 m

ST 1: Building Materials

1128

20 Questions
20 Marks
20 Mins

__Concept:__

Equation of motion:

It is defined as equations that describe the behaviour of a physical system in terms of its motion as a function of time.

There are three equation of motions:

- v = u + at
- \(s = ut + \frac 12at^2\)
- v2 = u2 + 2as

where u = initial velocity, v = final velocity, a = acceleration, s = displacement, t = time

__Calculation:__

__Given:__

u = 0 m/s, a = 5 m/s2, t = 5 s

\(s = ut + \frac 12at^2\)

\(s = 0\times t + \frac 12at^2\)

\(s = \frac 12at^2 = \frac 12 \times 5\times 5^2= 62.5 ~m\)