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Airforce Group X 13 Jul 2021 Shift 1 Memory Based Paper

Option 2 : Negative

**Concept:**

**Formula used:**

If f(x) = x^{n}, then f'(x) = n x^{n - 1}

__Calculations:__

Given:

**\(\rm f(x) = \dfrac{1}{3x\ +\ 5}\)**

Differentiating with respect to x, we get

⇒ f'(x) = \(- \dfrac{1}{(3x\ +\ 5)^2} \times 3\)

Put x = 0

f'(0) = \(\rm 3\over 25\)

**∴ The value of f'(1) is Negative**